Nanyang 2025 P6 Maths Prelim — Paper 1 Booklet B Q28 Solution

Paper 1 Booklet B · Q28 · 2 marks · Angles

Question

ABE and BCD are triangles. ABC is a straight line. AB = BE and BD = CD. $\angle EBD = 73^\circ$ and $\angle BCD = 55^\circ$. Find $\angle BEA$.

Answer: $64^\circ$

In triangle BCD, BD = CD, so $\angle DBC = \angle BCD = 55^\circ$. Since ABC is a straight line, $\angle ABE = 180^\circ - \angle EBD - \angle DBC = 180^\circ - 73^\circ - 55^\circ = 52^\circ$. In triangle ABE, AB = BE, so $\angle BEA = \angle BAE = (180^\circ - 52^\circ) \div 2 = 64^\circ$.

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