Tao Nan 2025 P6 Maths Prelim — Paper 2 Q12a Solution

Paper 2 · Q12a · 2 marks · Angles

Question

$ABCD$ is a parallelogram and $CFDE$ is a rhombus. $\angle ADG = 12^\circ$. Find $\angle w$.

Answer: $127^\circ$

$\angle DEC = \angle DFC = 74^\circ$ (rhombus). $\angle EHG = (180^\circ - 74^\circ) \div 2 = 53^\circ$. $\angle w = 180^\circ - 53^\circ = 127^\circ$.

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